0=288x-16x^2-1152

Solution for 0=288x-16x^2-1152 equation:

0=288x-16x^2-1152

We move all terms to the left:

0-(288x-16x^2-1152)=0

We add all the numbers together, and all the variables

-(288x-16x^2-1152)=0

We get rid of parentheses

16x^2-288x+1152=0

a = 16; b = -288; c = +1152;
Δ = b2-4ac
Δ = -2882-4·16·1152
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-288)-96}{2*16}=\frac{192}{32}
=6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-288)+96}{2*16}=\frac{384}{32}
=12
$